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mass of AgCl that will dissolve in 100l water = 196.46Based on the fact that solubility product of AgCl = 1.9 X 10^-4Dissociation of AgCl can be represented as follows,AgCl(s) ↔ Ag+(ag) + Cl-(aq)Let, [Ag+] = [Cl-] = S∴Ksp = [Ag+][Cl-] = S^2∴ S = √Ksp = √(1.9 X 10^-4) = 1.37x 10^-2 mol/dm3Now, Molarity of solution = weight of solute/ molecular weight x volume of solution.1.37x 10^-2 mol/dm3 = weight of AgCl(s)/ 143.4 x 100cross multiplyweight of AgCl(s) = 14340 x 1.37x 10^-2weight of AgCl(s) = 196.46 (approximated)Therefore, mass of AgCl that will dissolve in 100l water = 196.46...