The solutions to theVolumeofPyramidsand Cones1. 553.44 cm³   2. 338.92 cm³  3. 376.99 cm³ 4 . 636.69cm³How do we solve for the Volumes of Pyramids?The solve the followingvolumefor eachpyramid, we say;1. h = √slant height² - (1/2 base side length)²h = √(13² - (1/2 × 12)²)h =√(169 - 36)h = √(133) =V = 1/3 × 12² × √133V = 553.56cm³2. A =√(s×(s - a)(s - b)(s - c))s = (a + b + c) / 2 ⇒ (10 + 12 + 15) / 2 = 18.5A = √(18.5×(18.5 - 10)(18.5 - 12)(18.5 - 15)) ⇒ 59.81 cm²V = 1/3 × A × heightV = 1/3× 59.81 ×17 cm³ ⇒ 338.92 cm³3. V = 1/3× pi × 6² × 10 cm³V = 376.99  cm³The above answers are in response to the question in Unit 11 as seen below;1. A square pyramid has a base with side length 12 cm and a slant height of 13 cm. Find the volume of the pyramid.2. Atriangular pyramidhas a base with side lengths 10 cm, 12 cm, and 15 cm. The height of the pyramid is 17 cm. Find the volume of the pyramid.3. A cone has a radius of 6 cm and a height of 10 cm. Find the volume of the cone.4. A frustum of a cone has a top radius of 4 cm, a bottom radius of 6 cm, and a height of 8 cm. Find the volume of the frustum.Find more exercises onvolumeofpyramid;brainly.com/question/16632850#SPJ1...

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