Solved:
Answered by AI, Verified by Human Experts
The heat of vaporization of water is 40.66 kj/mol. how much heat is absorbed when 2.46 g of water boils at atmospheric pressure?
The heat of vaporization of water is 40.66 kj/mol. how much heat is absorbed when 2.46 g of water boils at atmospheric pressure?
Answer:The amount of heat absorbed by water is 5570.42 JExplanation:To calculate the number of moles, we use the equation:Given mass of water = 2.46 gMolar mass of water = 18 g/molPutting values in above equation, we get:To calculate the heat absorbed by water, we use the equation:where,= amount of heat absorbed = ? Jn = number of moles of water = 0.137 moles= heat of vaporization of water = 40.66 kJ/mol = 40660 J/mol(Conversion factor: 1 kJ = 1000 J)Putting values in above equation, we get:Hence, the amount of heat absorbed by water is 5570.42 J...
Unlock full access for 72 hours, watch your grades skyrocket.
For just $0.99 cents, get access to the powerful quizwhiz chrome extension that automatically solves your homework using AI. Subscription renews at $5.99/week.