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The curve y = |x|/ 5 − x2 is called a bullet-nose curve. find an equation of the tangent line to this curve at the point (2, 2).
The curve y = |x|/ 5 − x2 is called a bullet-nose curve. find an equation of the tangent line to this curve at the point (2, 2).
Theequationof the tangent line to the curve y = |x|/ 5 − x2 at the point (2, 2) is y = 9x - 16What's theequationabout?The slope of the tangent line at the point (2, 2) is given by the derivative of the curve at that point. The derivative of the curve isdy/dx = (5 - x²) / (5 * |x|)Evaluating thederivativeat x = 2, we getdy/dx = (5 - 2²) / (5 * |2|) = 0 / 10 = 16.Theequationof the tangent line through the point (2, 2) with slope 0 is y = 9x -16Therefore, the equation of the tangent line to the curve y = |x|/ 5 − x2 at the point (2, 2) is y = 9x - 16Learn more aboutequationbrainly.com/question/29174899#SPJ4...
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