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Solve for x, given the equation Square root of x minus 5 + 7 = 11. x = 21, solution is extraneous x = 21, solution is not extraneous x = 81, solution is extraneous x = 81, solution is not extraneous
Solve for x, given the equation Square root of x minus 5 + 7 = 11. x = 21, solution is extraneous x = 21, solution is not extraneous x = 81, solution is extraneous x = 81, solution is not extraneous
This is the concept of algebra, to solve the expression we proceed as follows:√(x-5)+7=11put like terms together:√(x-5)=11-7√(x-5)=4squaring both sides we get:x-5=16x=16+5x=21The solution is not extraneous....
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