Thefictional molecule"ArF4" suggests that it consists of one atom of Argon (Ar) and four atoms of Fluorine (F).Argonis a noble gas, and its Lewis dot structure consists of its symbol "Ar" with eight dots around it, representing its fullvalence shell.TheLewis dot structurefor ArF4 is given in the image attached below.Since Argon has eight valence electrons in its outermost shell (full octet), andFluorinehas seven electrons in its outermost shell, it's evident that each Fluorine atom contributes one electron to form asingle bondwith Argon.Regarding the 3D structure andpolarity:3D Structure: ArF4 doesn't form a stable molecule due to the electronic configuration of the elements. Noble gases like Argon generally don't form compounds with other elements, and the hypothetical molecule "ArF4" wouldn't be stable. However, if we imagine it being forced into a structure, it might resemble atetrahedral geometrywith Argon at the center and four Fluorine atoms bonded to it, one on each vertex of the tetrahedron.Polarity: If "ArF4" were to exist, it would be nonpolar. Fluorine is moreelectronegativethan Argon, and since each Argon-Fluorine bond would be polar (with the Fluorine end being more negative), the symmetry of the tetrahedral structure would cancel out the dipoles, resulting in anonpolar molecule.However, please note that the concept of "ArF4" is hypothetical, as noble gases likeArgonrarely form chemical compounds due to their stable electronic configurations.Learn more aboutArgonfrom the link given below.brainly.com/question/12032224#SPJ4...

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