From the given circuit thecurrentin resistor R is 2A, the resistance R is 5ohm,  the unknown emf E is 42V and if thecircuitis broken at point x, the current in resistor R is zero.Given the diagram, thevoltagepassing through resistor R (V) =  28VThecurrentpassing through resistor R is = I1The resistance of second resistor (R2) =6 ohm.The current passing through R2 = 4ATheresistanceof third resistor (R3) = 3 ohmThe current passing through R3 = 6AThe emf at resistor R2 = eHere we can see that current passing through R3 is split into I1 and I2 such that I1 + I2 = I3. Then, I1 + 4 = 6AI1 = 2A(a) The current inresistorR = 2A(b) From ohms law we know that V = IR. Then V1 - I3R3 -I1R1 = 028 - (3 x 6) - (2 x R) = 0. then R = 5ohm.The resistance R = 5 ohm(c) Similarly, e - (3 x 6) - ( 6 x 4) = 0Then e = 42VThe unknown emf = 42V(d) When the circuit is broken at x, thatbranchis eliminated from the circuit. It will stop carrying current. The distribution of currents and voltages in the otherportionsof the circuit will vary as a result.To learn more aboutresistanceclick herebrainly.com/question/29427458#SPJ4...

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