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Final answer:1.1.50 × 10^22atoms of calcium, 2. 1.08 × 10^22 atoms of iron, 3. 7.62 × 10^21 atoms of seleniumExplanation:1. How many atoms ofcalciumare in 1.00 g?The molar mass of calcium is 40.08 g/mol.Number of atoms of calcium = (1.00 g) / (40.08 g/mol) * (6.022 × 10^23 atoms/mol)Number of atoms of calcium = 1.50 × 10^22 atomsTherefore, there are 1.50 × 10^22 atoms of calcium in 1.00 g of calcium.2. How many atoms ofironare in 1.00 g?The molar mass of iron is 55.85 g/mol.Number of atoms of iron = (1.00 g) / (55.85 g/mol) * (6.022 × 10^23 atoms/mol)Number of atoms of iron = 1.08 × 10^22 atomsTherefore, there are 1.08 × 10^22 atoms of iron in 1.00 g of iron.3. How many atoms ofseleniumare in 1.00 g?The molar mass of selenium is 78.96 g/mol.Number of atoms of selenium = (1.00 g) / (78.96 g/mol) * (6.022 × 10^23 atoms/mol)Number of atoms of selenium = 7.62 × 10^21 atomsTherefore, there are 7.62 × 10^21 atoms of selenium in 1.00 g of selenium.Learn More AboutSeleniumatbrainly.com/question/29576848#SPJ11...