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A ship sets sail from rotterdam, the netherlands, heading due north at 7.00 m/s relative to the water. the local ocean current is 1.50 m/s in a direction 40.0º north of east. what is the magnitude of the velocity of the ship relative to the earth (in m/s)? answer
A ship sets sail from rotterdam, the netherlands, heading due north at 7.00 m/s relative to the water. the local ocean current is 1.50 m/s in a direction 40.0º north of east. what is the magnitude of the velocity of the ship relative to the earth (in m/s)? answer
Themagnitudeof the velocity of the ship relative to the earth is 8.04 m/s.How to solveLet the following be thevectors:v_sw: velocity of the ship relative to the waterv_c:velocityof the ocean currentv_se: velocity of the ship relative to the earthWe are given that v_sw = (7, 0) and v_c = (1.5 * cos(40), 1.5 * sin(40)). We can find v_se using thevector addition rule:v_se = v_sw + v_c= (7, 0) + (1.5 * cos(40), 1.5 * sin(40))= (7 + 1.5 * cos(40), 0 + 1.5 * sin(40))= (7.26, 0.97)Themagnitudeof v_se is:|v_se| = sqrt(v_se_x^2 + v_se_y^2)== 8.04 m/sTherefore, the magnitude of the velocity of the ship relative to the earth is 8.04 m/s.Read more aboutmagnitudehere"brainly.com/question/30337362#SPJ4...
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